Divide :

$6\dfrac{3}{16}$ ÷ $3\dfrac{1}{7}$

We have:

$\begin{array}{ll} \phantom{=} 6\dfrac{3}{16} ÷ 3\dfrac{1}{7} \\ = \dfrac{99}{16} ÷ \dfrac{22}{7} & \text{[Converting mixed to improper fraction]} \\ = \dfrac{99}{16} \times \dfrac{7}{22} & [\text{Reciprocal of } \dfrac{22}{7} \text{ is } \dfrac{7}{22}] \\ = \dfrac{9}{16} \times \dfrac{7}{2} & \text{[Simplifying 99 and 22 ⇒ Divide by 11]} \\ = \dfrac{9 \times 7}{16 \times 2} \\ = \dfrac{63}{32} \\ = 1\dfrac{31}{32} \end{array}$

∴ The answer is $1\dfrac{31}{32}$