Divide :

$9\dfrac{4}{5}$ ÷ $3\dfrac{23}{25}$

We have:

$\begin{array}{ll} \phantom{=} 9\dfrac{4}{5} ÷ 3\dfrac{23}{25} \\ = \dfrac{49}{5} ÷ \dfrac{98}{25} & \text{[Converting mixed to improper fraction]} \\ = \dfrac{49}{5} \times \dfrac{25}{98} & [\text{Reciprocal of } \dfrac{98}{25} \text{ is } \dfrac{25}{98}] \\ = \dfrac{1}{5} \times \dfrac{25}{2} & \text{[Simplifying 49 and 98 ⇒ Divide by 49]} \\ = \dfrac{1}{1} \times \dfrac{5}{2} & \text{[Simplifying 25 and 5 ⇒ Divide by 5]} \\ = \dfrac{1 \times 5}{1 \times 2} \\ = \dfrac{5}{2} \\ = 2\dfrac{1}{2} \end{array}$

∴ The answer is $2\dfrac{1}{2}$