Divide:
21738÷112192\dfrac{17}{38} ÷ 1\dfrac{12}{19}23817÷11912
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Solving,
⇒21738÷11219⇒9338÷3119⇒9338×1931⇒9331×1938⇒3×12⇒32⇒112.\Rightarrow 2\dfrac{17}{38} ÷ 1\dfrac{12}{19}\\[1em] \Rightarrow \dfrac{93}{38} ÷ \dfrac{31}{19}\\[1em] \Rightarrow \dfrac{93}{38} \times \dfrac{19}{31}\\[1em] \Rightarrow \dfrac{93}{31} \times \dfrac{19}{38}\\[1em] \Rightarrow 3 \times \dfrac{1}{2}\\[1em] \Rightarrow \dfrac{3}{2}\\[1em] \Rightarrow 1\dfrac{1}{2}.⇒23817÷11912⇒3893÷1931⇒3893×3119⇒3193×3819⇒3×21⇒23⇒121.
Hence, 21738÷11219=1122\dfrac{17}{38} ÷ 1\dfrac{12}{19} = 1\dfrac{1}{2}23817÷11912=121.
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