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Mathematics

Divide:

- 14x6y3 - 21x4y5 + 7x5y4 by 7x2y2

Algebraic Expressions

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Answer

(- 14x6y3 - 21x4y5 + 7x5y4) ÷ 7x2y2

= (- 14x6y3 ÷ 7x2y2) - (21x4y5 ÷ 7x2y2) + (7x5y4 ÷ 7x2y2)

= (\Big( - 147\dfrac{14}{7} x(6-2)y(3-2) )\Big) - (\Big( 217\dfrac{21}{7} x(4-2)y(5-2) )\Big) - (\Big( - 77\dfrac{7}{7} x(5-2)y(4-2) )\Big)

= - 2 x4y1 - 3 x2y3 + 1 x3y2

Hence, (- 14x6y3 - 21x4y5 + 7x5y4) ÷ 7x2y2 = - 2 x4y - 3 x2y3 + x3y2

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