Draw a circle of radius 3.5 cm. Draw any two of its (non-parallel) chords. Construct the perpendicular bisectors of these chords. Where do they meet?

Steps:

1. Mark a point O on the sheet of paper as the centre of the circle.

2. With O as centre and radius 3.5 cm, draw a circle.

3. Draw any two non-parallel chords AB and CD of the circle.

4. Construct the perpendicular bisector of chord AB. For this, take A and B as centres and equal radius $\left(\gt\dfrac{1}{2}\text{AB}\right)$, draw arcs on both sides of AB, and join the points of intersection of the arcs.

5. Similarly, construct the perpendicular bisector of chord CD.

On examining, we find that the perpendicular bisectors of the two chords meet at the centre O of the circle.

Hence, the perpendicular bisectors of the two chords meet at the centre of the circle.