Mathematics
Draw the graph of equation x + 2y - 3 = 0. From the graph, find :
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = -2.
Coordinate Geometry
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Answer
Step 1:
Give at least three suitable values to the variable x and find the corresponding values of y.
Let x = -1, then (-1) + 2y - 3 = 0 ⇒ y = 2
Let x = 0, then 0 + 2y - 3 = 0 ⇒ y = 1.5
Let x = 1, then 1 + 2y - 3 = 0 ⇒ y = 1
Step 2:
Make a table (as given below) for the different pairs of the values of x and y:
| x | -1 | 0 | 1 |
|---|---|---|---|
| y | 2 | 1.5 | 1 |
Step 3:
Plot the points, from the table, on a graph paper and then draw a straight line AB passing through the points plotted on the graph.

(i) To find x1, the value of x, when y = 3:
Through the point y = 3, draw a horizontal straight line which meets the line AB at point C. Through point C, draw a vertical line which meets the x-axis at x = -3.
Hence, the value of x, when y = 3 is -3 , i.e, x1 = -3.
(ii) To find x2, the value of x, when y = -2:
Through the point y = -2, draw a horizontal straight line which meets the line AB at point D. Now, through point D, draw a vertical line which meets the y-axis at x = 7.
Hence, the value of x, when y = -2 is 7 , i.e, x2 = 7.
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