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Mathematics

Draw the graph for the linear equation given below :

x3=25(y+1)x - 3 = \dfrac{2}{5}(y + 1)

Coordinate Geometry

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Answer

x3=25(y+1)x - 3 = \dfrac{2}{5}(y + 1)

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = 0, then 03=25(y+1)y=8.50 - 3 = \dfrac{2}{5}(y + 1) ⇒ y = -8.5

Let x = 1, then 13=25(y+1)y=61 - 3 = \dfrac{2}{5}(y + 1) ⇒ y = -6

Let x = 3, then 33=25(y+1)y=13 - 3 = \dfrac{2}{5}(y + 1) ⇒ y = -1

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

x013
y-8.5-6-1

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Draw the graph for the linear equation given below : Co-ordinate Geometry, Concise Mathematics Solutions ICSE Class 9.

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