KnowledgeBoat Logo
|

Mathematics

Draw the graph for the linear equation given below :

y=32x+23y =\dfrac{3}{2}x + \dfrac{2}{3}

Coordinate Geometry

13 Likes

Answer

y=32x+23y =\dfrac{3}{2}x + \dfrac{2}{3}

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = -2, then y=32×(2)+23y=2.3y =\dfrac{3}{2} \times (-2) + \dfrac{2}{3} ⇒ y = -2.3

Let x = 0, then y=32×0+23y=0.6y =\dfrac{3}{2} \times 0 + \dfrac{2}{3} ⇒ y = 0.6

Let x = 2, then y=32×2+23y=3.6y =\dfrac{3}{2} \times 2 + \dfrac{2}{3} ⇒ y = 3.6

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

x-202
y-2.30.63.6

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Draw the graph for the linear equation given below : Co-ordinate Geometry, Concise Mathematics Solutions ICSE Class 9.

Answered By

3 Likes


Related Questions