Mathematics

Draw the graph for the linear equation given below :
3y + 5 = 0

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3y + 5 = 0

⇒ 3y = - 5

⇒ y = - $\dfrac{5}{3}$

⇒ y = - 1.6

The graph of 3y + 5 = 0 is the straight line which is parallel to the x-axis at a distance of - 1.6 units from it.

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