For equation $\dfrac{x}{3}-\dfrac{y}{2}$ = 1, the value of y for x = 9 is :

1. -4

2. 6

3. 4

4. -6

Lines x - 4 = 0 and 3y = 1 intersect each other at point P. The co-ordinates of point P are:

1. $\Big(4,-\dfrac{1}{3}\Big)$

2. $\Big(4,\dfrac{1}{3}\Big)$

3. $\Big(-4,\dfrac{1}{3}\Big)$

4. $\Big(-4,-\dfrac{1}{3}\Big)$

Draw the graph for the linear equation given below :

x + 3 = 0

Draw the graph for the linear equation given below :

x - 5 = 0