Draw the graph of the straight line given by the equation 4x - 3y + 36 = 0

Calculate the area of the triangle formed by the line drawn and the co-ordinate axes.

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = -9, then 4 $\times$ (-9) - 3y + 36 = 0 ⇒ y = 0

Let x = -6, then 4 $\times$ (-6) - 3y + 36 = 0 ⇒ y = 4

Let x = -3, then 4 $\times$ (-3) - 3y + 36 = 0 ⇒ y = 8

Let x = 0, then 4 $\times$ 0 - 3y + 36 = 0 ⇒ y = 12

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Area of triangle OAB = $\dfrac{1}{2}$ OA x OB

= $\dfrac{1}{2}$ x 9 x 12 square units

= $\dfrac{1}{2}$ x 108 square units

= 54 square units

Hence, area of triangle = 54 sq. units.