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Mathematics

Draw an ogive for the following frequency distribution :

Class - intervalFrequency
10 - 1921
20 - 2915
30 - 3912
40 - 4919
50 - 598

Statistics

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Answer

The above frequency distribution is discontinuous, to convert it into continuous frequency distribution,

Adjustment factor=Lower limit of one class - Upper limit of previous class2=20192=12=0.5\Rightarrow \text{Adjustment factor} = \dfrac{\text{Lower limit of one class - Upper limit of previous class}}{2} \\[1em] = \dfrac{20 - 19}{2} \\[1em] = \dfrac{1}{2} \\[1em] = 0.5

Subtract the adjustment factor (0.5) from all the lower limits and add the adjustment factor (0.5) to all the upper limits.

Continuous frequency distribution for the given data is :

Classes before adjustmentClasses after adjustmentFrequencyCumulative frequency
10 - 199.5 - 19.52121
20 - 2919.5 - 29.51536 (21 + 15)
30 - 3929.5 - 39.51248 (36 + 12)
40 - 4939.5 - 49.51967 (48 + 19)
50 - 5949.5 - 59.5875 (67 + 8)

Steps of construction :

  1. Since, the scale on x-axis starts at 9.5, a break (kink) is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 9.5.

  2. Take 2 cm along x-axis = 10 units

  3. Take 1 cm along y-axis = 10 units

  4. Ogive always starts from a point on x-axis representing the lower limit of the first class. Mark point (9.5, 0).

  5. Take upper class limits along x-axis and corresponding cumulative frequencies along y-axis, mark the points (19.5, 21), (29.5, 36), (39.5, 48), (49.5, 67), (59.5, 75).

  6. Join the points marked by a free hand curve.

The required ogive is shown in the below figure:

Draw an ogive for the following frequency distribution. Graphical Representation of Statistical Data, RSA Mathematics Solutions ICSE Class 10.

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