The equation of a line with slope m and passing through a point P(a, b), is given by :
(y – a) = m(x – b)
(x – b) = m(y – a)
(x – a) = m(y – b)
(y – b) = m(x – a)
Straight Line Eq
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Question

The equation of a line with slope m and passing through a point P(a, b), is given by : 1. (y – a) = m(x – b) 2. (x – b) = m(y – a) 3. (x – a) = m(y – b) 4. (y – b) = m(x – a)

KnowledgeBoat · Accepted Answer

By point-slope form, Equation of line : y - y1 = m (x - x1) Thus, equation of line passing through (a, b) and slope m is : y - b = m(x - a) Hence, option 4 is the correct option.

Mathematics

The equation of a line with slope m and passing through a point P(a, b), is given by :
(y – a) = m(x – b)
(x – b) = m(y – a)
(x – a) = m(y – b)
(y – b) = m(x – a)

Straight Line Eq

Answer

Related Questions

The equation of a line with slope m and y-intercept c is given by:
x = my + c
cy = mx
y = mx + c
none of these

The slope m of a line whose inclination is α, is given by :
sin α
cos α
tan α
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The equation of a line with slope m and passing through (0, 0) is :
x = my
y = mx
m = y – x
m = y + x

Mathematics

The equation of a line with slope m and passing through a point P(a, b), is given by :(y – a) = m(x – b)(x – b) = m(y – a)(x – a) = m(y – b)(y – b) = m(x – a)