Mathematics
The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is:
x – 3y + 1 = 0
3x + y + 1 = 0
3x – y – 1 = 0
3x – y + 1 = 0
Straight Line Eq
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Answer
The given line is , so its slope is m = 3.
Since the required line is parallel, its slope is also m = 3.
Using the point-slope form y - y1 = m(x - x1) with the point (x1, y1) = (1, 2) and m=3:
y - 2 = 3(x - 1)
y - 2 = 3x - 3
Rearranging the equation to the standard form (Ax + By + C = 0):
0 = 3x - y - 3 + 2
3x - y - 1 = 0
Hence, option 3 is the correct option.
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