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Chemistry

Ethane C2H6 burns in oxygen to produce carbon dioxide and water as shown in the equation given below:

2C2H6 + 7O2 ⟶ 4CO2 + 6H2O

Calculate the composition of the resulting gaseous mixture at room temperature when 60 c.c. of ethane burns in 250 c.c. of oxygen.

Organic Chemistry

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Answer

2C2H6+7O2⟶4CO2+6H2O2 vol.:7 vol.⟶4 vol.\begin{matrix} 2\text{C}2\text{H}6 & + & 7\text{O}2 & \longrightarrow & 4\text{CO}2 & + & 6\text{H}_2\text{O} \\ 2 \text{ vol.} & : & 7 \text{ vol.} & \longrightarrow & 4 \text{ vol.} & \\ \end{matrix}

[By Gay Lussac's law]

2 Vol. of C2H6 requires 7 Vol. of oxygen

∴ 60 cc C2H6 will require 72\dfrac{7}{2} x 60

= 210 cc of Oxygen

Hence, unused oxygen = 250 - 210 = 40 cc

Similarly,

2 Vol. of C2H6 produces 4 Vol. of carbon dioxide

∴ 60 cc C2H6 produces 42\dfrac{4}{2} x 60

= 120 cc of Carbon dioxide

Hence, carbon dioxide produced = 120 cc.

The gaseous mixture at room temperature (assuming water condenses) contains 120 cc CO2 and 40 cc O2.

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