Evaluate:
cos 22°sin 68°\dfrac{\text{cos 22°}}{\text{sin 68°}}sin 68°cos 22°
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cos 22°sin 68°=cos (90° - 68°)sin 68°=sin 68°sin 68°=sin68°sin68°=1\dfrac{\text{cos 22°}}{\text{sin 68°}} = \dfrac{\text{cos (90° - 68°)}}{\text{sin 68°}}\\[1em] = \dfrac{\text{sin 68°}}{\text{sin 68°}}\\[1em] = \dfrac{\cancel{sin 68°}}{\cancel{sin 68°}}\\[1em] = 1sin 68°cos 22°=sin 68°cos (90° - 68°)=sin 68°sin 68°=sin68°sin68°=1
Hence, cos 22°sin 68°\dfrac{\text{cos 22°}}{\text{sin 68°}}sin 68°cos 22° = 1.
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The value of :
cosec 40° cos 50° + sin 50° sec 40° is:
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In a triangle ABC, secA+C2\text{sec}\dfrac{A + C}{2}sec2A+C is equal to:
secB2\text{sec}\dfrac{B}{2}sec2B
cosec B
cosecB2\text{cosec}\dfrac{B}{2}cosec2B
tan 47°cot 43°\dfrac{\text{tan 47°}}{\text{cot 43°}}cot 43°tan 47°
sec 75°cosec 15°\dfrac{\text{sec 75°}}{\text{cosec 15°}}cosec 15°sec 75°
