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Mathematics

Evaluate :

[2cos60°2sin30°tan45°cos0°][cot45°cosec30°sec60°sin90°]\begin{bmatrix}[r] 2cos60° & -2sin30° \ -tan 45° & cos0° \end{bmatrix}\begin{bmatrix}[r] cot 45° & cosec 30° \ sec60° & sin 90° \end{bmatrix}

Matrices

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Answer

Given,

[2cos60°2sin30°tan45°cos0°][cot45°cosec30°sec60°sin90°][2×122×1211][1221][1111][1221][1×1+(1)×21×2+(1)×11×1+1×21×2+1×1][12211+22+1][1111].\Rightarrow \begin{bmatrix}[r] 2cos60° & -2sin30° \ -tan 45° & cos0° \end{bmatrix}\begin{bmatrix}[r] cot 45° & cosec 30° \ sec60° & sin 90° \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] 2 \times \dfrac{1}{2} & -2 \times \dfrac{1}{2} \ -1 & 1 \end{bmatrix}\begin{bmatrix}[r] 1 & 2 \ 2 & 1 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] 1 & -1 \ -1 & 1 \end{bmatrix}\begin{bmatrix}[r] 1 & 2 \ 2 & 1 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] 1 \times 1 + (-1) \times 2 & 1 \times 2 + (-1) \times 1 \ -1 \times 1 + 1 \times 2 & -1 \times 2 + 1 \times 1 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] 1 - 2 & 2 - 1 \ -1 + 2 & -2 + 1 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] -1 & 1 \ 1 & -1 \end{bmatrix}.

Hence, [2cos60°2sin30°tan45°cos0°][cot45°cosec30°sec60°sin90°]=[1111].\begin{bmatrix}[r] 2cos60° & -2sin30° \ -tan 45° & cos0° \end{bmatrix}\begin{bmatrix}[r] cot 45° & cosec 30° \ sec60° & sin 90° \end{bmatrix} = \begin{bmatrix}[r] -1 & 1 \ 1 & -1 \end{bmatrix}.

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