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Mathematics

Evaluate :

log 4+13 log 12515 log 32\text{log 4} + \dfrac{1}{3}\text{ log 125} - \dfrac{1}{5}\text{ log 32}

Logarithms

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Answer

Evaluating the expression,

log 4+13 log 12515 log 32log 4+13 log 5315 log 25log 4 + log (5)(3×13)log (2)(5×15)log 4 + log 5 - log 2log 4×52log 202log 101.\Rightarrow \text{log 4} + \dfrac{1}{3}\text{ log 125} - \dfrac{1}{5}\text{ log 32} \\[1em] \Rightarrow \text{log 4} + \dfrac{1}{3}\text{ log 5}^3 - \dfrac{1}{5}\text{ log 2}^5 \\[1em] \Rightarrow \text{log 4 + log (5)}^{\Big(3 \times \dfrac{1}{3}\Big)} - \text{log (2)}^{\Big(5 \times \dfrac{1}{5}\Big)} \\[1em] \Rightarrow \text{log 4 + log 5 - log 2} \\[1em] \Rightarrow \text{log } \dfrac{4 \times 5}{2} \\[1em] \Rightarrow \text{log } \dfrac{20}{2} \\[1em] \Rightarrow \text{log } 10 \\[1em] \Rightarrow 1.

Hence, log 4+13 log 12515 log 32\text{log 4} + \dfrac{1}{3}\text{ log 125} - \dfrac{1}{5}\text{ log 32} = 1.

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