Evaluating,
⇒loga bc+11+logb ca+11+logc ab+11⇒log alog bc+11+log blog ca+11+log clog ab+11⇒log alog bc + log a1+log blog ca + log b1+log clog ab + log c1⇒log bc + log alog a+log ca + log blog b+log ab + log clog c⇒log b + log c + log alog a+log c + log a + log blog b+log a + log b + log clog c⇒log a + log b + log clog a + log b + log c⇒1.
Hence, loga bc+11+logb ca+11+logc ab+11 = 1.