Evaluate:
1−15+5−12\dfrac{1}{-15} + \dfrac{5}{-12}−151+−125
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−115+−512\dfrac{-1}{15} + \dfrac{-5}{12} \\[1em]15−1+12−5
LCM of 15 and 12 is 2 x 2 x 3 x 5 = 60
−1×415×4+−5×512×5=−460+−2560=−4+(−25)60=−2960\dfrac{-1 \times 4}{15 \times 4} + \dfrac{-5 \times 5}{12 \times 5} \\[1em] =\dfrac{-4}{60} + \dfrac{-25}{60} \\[1em] =\dfrac{-4 + (-25)}{60} \\[1em] =\dfrac{-29}{60}15×4−1×4+12×5−5×5=60−4+60−25=60−4+(−25)=60−29
∴ 1−15+5−12=−2960\dfrac{1}{-15} + \dfrac{5}{-12} = \dfrac{-29}{60}−151+−125=60−29
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