Evaluate:
23−45\dfrac{2}{3} - \dfrac{4}{5}32−54
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LCM of 3 and 5 is 3 x 5 = 15
2×53×5−4×35×3=1015−1215=10−1215=−215\dfrac{2 \times 5}{3 \times 5} - \dfrac{4 \times 3}{5 \times 3}\\[1em] = \dfrac{10}{15} - \dfrac{12}{15}\\[1em] = \dfrac{10 - 12}{15}\\[1em] = \dfrac{-2}{15}3×52×5−5×34×3=1510−1512=1510−12=15−2
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The number subtracted from 5235\dfrac{2}{3}532 to get -1231\dfrac{2}{3}132 is :
4
-7137\dfrac{1}{3}731
6136\dfrac{1}{3}631
7137\dfrac{1}{3}731
The number added to 5235\dfrac{2}{3}532 to get -1231\dfrac{2}{3}132 is :
−49−2−3\dfrac{-4}{9} - \dfrac{2}{-3}9−4−−32
−1−49-1 - \dfrac{4}{9}−1−94
