Evaluate:
76×−1891\dfrac{7}{6} \times \dfrac{-18}{91}67×91−18
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76×−1891=7×(−18)6×91=−126546=−313\dfrac{7}{6} \times \dfrac{-18}{91}\\[1em] =\dfrac{7 \times (-18)}{6 \times 91}\\[1em] =\dfrac{-126}{546}\\[1em] =\dfrac{-3}{13}67×91−18=6×917×(−18)=546−126=13−3
Hence, 76×−1891=−313\dfrac{7}{6} \times \dfrac{-18}{91} = \dfrac{-3}{13}67×91−18=13−3
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The product of a rational number 27\dfrac{2}{7}72 and its additive inverse is:
449\dfrac{4}{49}494
−47\dfrac{-4}{7}7−4
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−145×−67\dfrac{-14}{5} \times \dfrac{-6}{7}5−14×7−6
−12572×9−5\dfrac{-125}{72} \times \dfrac{9}{-5}72−125×−59
−119×−51−44\dfrac{-11}{9} \times \dfrac{-51}{-44}9−11×−44−51
