Evaluate:
(−5×215)−(−6×29)\Big(-5 \times \dfrac{2}{15}\Big) - \Big(-6 \times \dfrac{2}{9}\Big)(−5×152)−(−6×92)
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(−5×21×15)−(−6×21×9)=(−1015)−(−129)=(−23)−(−43)=(−2−(−4)3)=(−2+43)=(23)\Big(\dfrac{-5 \times 2}{1 \times 15}\Big) - \Big(\dfrac{-6 \times 2}{1 \times 9}\Big)\\[1em] =\Big(\dfrac{-10}{15}\Big) - \Big(\dfrac{-12}{9}\Big)\\[1em] =\Big(\dfrac{-2}{3}\Big) - \Big(\dfrac{-4}{3}\Big)\\[1em] =\Big(\dfrac{-2 - (-4)}{3}\Big)\\[1em] =\Big(\dfrac{-2 + 4}{3})\\[1em] =\Big(\dfrac{2}{3}\Big)(1×15−5×2)−(1×9−6×2)=(15−10)−(9−12)=(3−2)−(3−4)=(3−2−(−4))=(3−2+4)=(32)
Hence, (−5×512)−(−6×29)=(23)\Big(-5 \times \dfrac{5}{12}\Big) - \Big(-6 \times \dfrac{2}{9}\Big) = \Big(\dfrac{2}{3}\Big)(−5×125)−(−6×92)=(32)
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(2−3×54)+(59×3−10)\Big(\dfrac{2}{-3} \times \dfrac{5}{4}\Big) + \Big(\dfrac{5}{9} \times \dfrac{3}{-10}\Big)(−32×45)+(95×−103)
(2×14)−(−187×−715)\Big(2 \times \dfrac{1}{4}\Big) - \Big(\dfrac{-18}{7} \times \dfrac{-7}{15}\Big)(2×41)−(7−18×15−7)
(85×−32)+(−310×916)\Big(\dfrac{8}{5} \times \dfrac{-3}{2}\Big) + \Big(\dfrac{-3}{10} \times \dfrac{9}{16}\Big)(58×2−3)+(10−3×169)
Multiply each rational number, given below, by one (1):
7−5\dfrac{7}{-5}−57