Evaluate:
(2−3×54)+(59×3−10)\Big(\dfrac{2}{-3} \times \dfrac{5}{4}\Big) + \Big(\dfrac{5}{9} \times \dfrac{3}{-10}\Big)(−32×45)+(95×−103)
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(2×5−3×4)+(5×39×(−10))=(10−12)+(15−90)=(−56)+(−16)=(−5+(−1)6)=(−66)=−1\Big(\dfrac{2 \times 5}{-3 \times 4}\Big) + \Big(\dfrac{5 \times 3}{9 \times (-10)}\Big)\\[1em] =\Big(\dfrac{10}{-12}\Big) + \Big(\dfrac{15}{-90}\Big)\\[1em] =\Big(\dfrac{-5}{6}\Big) + \Big(\dfrac{-1}{6}\Big)\\[1em] =\Big(\dfrac{-5 + (-1)}{6}\Big)\\[1em] =\Big(\dfrac{-6}{6}\Big)\\[1em] =-1(−3×42×5)+(9×(−10)5×3)=(−1210)+(−9015)=(6−5)+(6−1)=(6−5+(−1))=(6−6)=−1
Hence, (2−3×54)+(59×3−10)=(−66)\Big(\dfrac{2}{-3} \times \dfrac{5}{4}\Big) + \Big(\dfrac{5}{9} \times \dfrac{3}{-10}\Big) = \Big(\dfrac{-6}{6}\Big)(−32×45)+(95×−103)=(6−6)
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Multiply:
36−7\dfrac{36}{-7}−736 and −928\dfrac{-9}{28}28−9
−710\dfrac{-7}{10}10−7 and −815\dfrac{-8}{15}15−8
(2×14)−(−187×−715)\Big(2 \times \dfrac{1}{4}\Big) - \Big(\dfrac{-18}{7} \times \dfrac{-7}{15}\Big)(2×41)−(7−18×15−7)
(−5×215)−(−6×29)\Big(-5 \times \dfrac{2}{15}\Big) - \Big(-6 \times \dfrac{2}{9}\Big)(−5×152)−(−6×92)
