Evaluate: x5+n×(x2)3n+1x7n−2\dfrac{x^{5+n}\times(x^2)^{3n+1}}{x^{7n-2}}x7n−2x5+n×(x2)3n+1
2 Likes
x5+n×(x2)3n+1x7n−2=x5+n×(x)2(3n+1)x7n−2=x5+n×(x)6n+2x7n−2=x(5+n)+(6n+2)x7n−2=x5+n+6n+2x7n−2=x(7+7n)−(7n−2)=x7+7n−7n+2=x9\dfrac{x^{5+n}\times(x^2)^{3n+1}}{x^{7n-2}}\\[1em] = \dfrac{x^{5+n}\times(x)^{2(3n+1)}}{x^{7n-2}}\\[1em] = \dfrac{x^{5+n}\times(x)^{6n+2}}{x^{7n-2}}\\[1em] = \dfrac{x^{(5+n)+(6n+2)}}{x^{7n-2}}\\[1em] = \dfrac{x^{5+n+6n+2}}{x^{7n-2}}\\[1em] = x^{(7+7n)-(7n-2)}\\[1em] = x^{7+7n-7n+2}\\[1em] = x^{9}x7n−2x5+n×(x2)3n+1=x7n−2x5+n×(x)2(3n+1)=x7n−2x5+n×(x)6n+2=x7n−2x(5+n)+(6n+2)=x7n−2x5+n+6n+2=x(7+7n)−(7n−2)=x7+7n−7n+2=x9
x5+n×(x2)3n+1x7n−2=x9\dfrac{x^{5+n}\times(x^2)^{3n+1}}{x^{7n-2}} = x^{9}x7n−2x5+n×(x2)3n+1=x9
Answered By
1 Like
Simplify and express as positive indices:
(xy)m−n.(yz)n−l.(zx)l−m(xy)^{m-n}.(yz)^{n-l}.(zx)^{l-m}(xy)m−n.(yz)n−l.(zx)l−m
Show that: [xax−b]a−b.[xbx−c]b−c.[xcx−a]c−a=1\Big[\dfrac{x^a}{x^{-b}}\Big]^{a-b}.\Big[\dfrac{x^b}{x^{-c}}\Big]^{b-c}.\Big[\dfrac{x^c}{x^{-a}}\Big]^{c-a} = 1[x−bxa]a−b.[x−cxb]b−c.[x−axc]c−a=1
Evaluate: a2n+1×a(2n+1)(2n−1)an(4n−1)×(a2)2n+3\dfrac{a^{2n+1}\times a^{(2n+1)(2n-1)}}{a^{n(4n-1)}\times (a^2)^{2n+3}}an(4n−1)×(a2)2n+3a2n+1×a(2n+1)(2n−1)
Prove that: (m+n)−1(m−1+n−1)=(mn)−1(m + n)^{-1}(m^{-1} + n^{-1}) = (mn)^{-1}(m+n)−1(m−1+n−1)=(mn)−1