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Mathematics

Evaluate:

[5+22125]×0.1691.6\sqrt{\Big[5 + 2\dfrac{21}{25}\Big] \times \dfrac{0.169}{1.6}}

Sq & Sq Roots

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Answer

[5+22125]×0.1691.6=[5+7125]×169×1016×1000=[51+7125]×169×1016×1000=[5×251×25+7125]×16916×100=[12525+7125]×16916×100=[125+7125]×1691600=[19625]×1691600=[14×145×5]×13×1340×40=[145]×1340=[14×135×40]=[182200]=[91100]=0.91\sqrt{\Big[5 + 2\dfrac{21}{25}\Big] \times \dfrac{0.169}{1.6}}\\[1em] = \sqrt{\Big[5 + \dfrac{71}{25}\Big] \times \dfrac{169 \times 10}{16 \times 1000}}\\[1em] = \sqrt{\Big[\dfrac{5}{1} + \dfrac{71}{25}\Big] \times \dfrac{169 \times 10}{16 \times 1000}}\\[1em] = \sqrt{\Big[\dfrac{5 \times 25}{1 \times 25} + \dfrac{71}{25}\Big] \times \dfrac{169}{16 \times 100}}\\[1em] = \sqrt{\Big[\dfrac{125}{25} + \dfrac{71}{25}\Big] \times \dfrac{169}{16 \times 100}}\\[1em] = \sqrt{\Big[\dfrac{125 + 71}{25}\Big] \times \dfrac{169}{1600}}\\[1em] = \sqrt{\Big[\dfrac{196}{25}\Big] \times \dfrac{169}{1600}}\\[1em] = \sqrt{\Big[\dfrac{14\times 14}{5 \times 5}\Big] \times \dfrac{13 \times 13}{40 \times 40}}\\[1em] = \Big[\dfrac{14}{5}\Big] \times \dfrac{13}{40}\\[1em] = \Big[\dfrac{14 \times 13}{5 \times 40}\Big]\\[1em] = \Big[\dfrac{182}{200}\Big]\\[1em] = \Big[\dfrac{91}{100}\Big]\\[1em] = 0.91

[5+22125]×0.1691.6=0.91\sqrt{\Big[5 + 2\dfrac{21}{25}\Big] \times \dfrac{0.169}{1.6}} = 0.91

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