Evaluate: (a/2 - b/3) (a/2 + b/3)

Using the formula [∵ (x \+ y)(x \- y) = x 2 \- y 2 ] = = Hence, =

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$\Big(\dfrac{a}{2} -\dfrac{b}{3}\Big)$ $\Big(\dfrac{a}{2} +\dfrac{b}{3}\Big)$

Using the formula

[∵ (x + y)(x - y) = x² - y²]

= $\Big(\dfrac{a}{2}\Big)^2 - \Big(\dfrac{b}{3}\Big)^2$

= $\Big(\dfrac{a^2}{4}\Big) - \Big(\dfrac{b^2}{9}\Big)$

Hence, $\Big(\dfrac{a}{2} -\dfrac{b}{3}\Big)$ $\Big(\dfrac{a}{2} +\dfrac{b}{3}\Big)$ = $\Big(\dfrac{a^2}{4}\Big) - \Big(\dfrac{b^2}{9}\Big)$

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