Evaluate: (z - 2/3) (z + 2/3)

Using the formula [∵ (x \+ y)(x \- y) = x 2 \- y 2 ] = z 2 \- 2 = z 2 \- Hence, = z 2 \-

Mathematics

8 Likes

$\Big(z -\dfrac{2}{3}\Big)$ $\Big(z +\dfrac{2}{3}\Big)$

Using the formula

[∵ (x + y)(x - y) = x² - y²]

= z² - $\Big(\dfrac{2}{3}\Big)$ ²

= z² - $\dfrac{4}{9}$

Hence, $\Big(z -\dfrac{2}{3}\Big)$ $\Big(z +\dfrac{2}{3}\Big)$ = z² - $\dfrac{4}{9}$

Answered By

4 Likes