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Mathematics

Evaluate:

1012 - 1002

Sq & Sq Roots

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Answer

According to the property of square numbers, for any natural number n,

(n+1)2n2=(n+1)+n(n+1)^2 - n^2 = (n+1) + n

10121002=101+100=201101^2 - 100^2\\[1em] = 101 + 100\\[1em] = 201

Hence, 10121002=201101^2 - 100^2 = 201

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