Mathematics
Evaluate:
(a + bc) (a - bc) (a2 + b2c2)
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Answer
(a + bc) (a - bc) (a2 + b2c2)
Using the formula
[∵ (x + y)(x - y) = x2 - y2]
= [a2 - (bc)2] (a2 + b2c2)
= (a2 - b2c2) (a2 + b2c2)
= (a2)2 - (b2c2)2
= a4 - b4c4
Hence, (a + bc) (a - bc) (a2 + b2c2) = a4 - b4c4
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