Evaluate the following :
(14)−2−3×(8)23×50+(916)−12\Big(\dfrac{1}{4}\Big)^{-2} - 3 \times (8)^{\dfrac{2}{3}} \times 5^0 + \Big(\dfrac{9}{16}\Big)^{-\dfrac{1}{2}}(41)−2−3×(8)32×50+(169)−21
2 Likes
Given,
Simplifying the expression :
⇒(14)−2−3×(8)23×50+(916)−12⇒(4)2−3×[(2)3]23×1+(169)12⇒16−3×(2)2×1+[(43)2]12⇒16−12+43⇒4+43⇒12+43⇒163=513.\Rightarrow \Big(\dfrac{1}{4}\Big)^{-2} - 3 \times (8)^{\dfrac{2}{3}} \times 5^0 + \Big(\dfrac{9}{16}\Big)^{-\dfrac{1}{2}} \\[1em] \Rightarrow (4)^2 - 3 \times [(2)^3]^{\dfrac{2}{3}} \times 1 + \Big(\dfrac{16}{9}\Big)^{\dfrac{1}{2}} \\[1em] \Rightarrow 16 - 3 \times (2)^2 \times 1 + \Big[\Big(\dfrac{4}{3}\Big)^2\Big]^{\dfrac{1}{2}} \\[1em] \Rightarrow 16 - 12 + \dfrac{4}{3} \\[1em] \Rightarrow 4 + \dfrac{4}{3} \\[1em] \Rightarrow \dfrac{12 + 4}{3} \\[1em] \Rightarrow \dfrac{16}{3} = 5\dfrac{1}{3}.⇒(41)−2−3×(8)32×50+(169)−21⇒(4)2−3×[(2)3]32×1+(916)21⇒16−3×(2)2×1+[(34)2]21⇒16−12+34⇒4+34⇒312+4⇒316=531.
Hence, (14)−2−3×(8)23×50+(916)−12=513\Big(\dfrac{1}{4}\Big)^{-2} - 3 \times (8)^{\dfrac{2}{3}} \times 5^0 + \Big(\dfrac{9}{16}\Big)^{-\dfrac{1}{2}} = 5\dfrac{1}{3}(41)−2−3×(8)32×50+(169)−21=531.
Answered By
Evaluate :
(0.001)−13(0.001)^{-\dfrac{1}{3}}(0.001)−31
(0.027)−23(0.027)^{\dfrac{-2}{3}}(0.027)3−2
14+(0.01)−12−(27)23×30\sqrt{\dfrac{1}{4}} + (0.01)^{\dfrac{-1}{2}} - (27)^{\dfrac{2}{3}} \times 3^041+(0.01)2−1−(27)32×30
(8116)−34×[(259)−32÷(52)−3]\Big(\dfrac{81}{16}\Big)^{-\dfrac{3}{4}} \times \Big[\Big(\dfrac{25}{9}\Big)^{-\dfrac{3}{2}} ÷ {\Big(\dfrac{5}{2}\Big)^{-3}}\Big](1681)−43×[(925)−23÷(25)−3]
