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Mathematics

Evaluate the following :

(1681)34×(499)32÷(343216)23\Big(\dfrac{16}{81}\Big)^{-\dfrac{3}{4}} \times \Big(\dfrac{49}{9}\Big)^{\dfrac{3}{2}} ÷ \Big(\dfrac{343}{216}\Big)^{\dfrac{2}{3}}

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Answer

Given,

(1681)34×(499)32÷(343216)23\Big(\dfrac{16}{81}\Big)^{-\dfrac{3}{4}} \times \Big(\dfrac{49}{9}\Big)^{\dfrac{3}{2}} ÷ \Big(\dfrac{343}{216}\Big)^{\dfrac{2}{3}}

Simplifying the expression :

(1681)34×(499)32÷(343216)23(8116)34×[(73)2]32÷[(76)3]23[(32)4]34×[(73)2]32÷[(76)3]23(32)3×(73)3÷(76)2(278)×[(34327)÷(4936)](278)×[(34327)×(3649)](278)×(73)×4(92)×7632=3112.\Rightarrow \Big(\dfrac{16}{81}\Big)^{-\dfrac{3}{4}} \times \Big(\dfrac{49}{9}\Big)^{\dfrac{3}{2}} ÷ \Big(\dfrac{343}{216}\Big)^{\dfrac{2}{3}} \\[1em] \Rightarrow \Big(\dfrac{81}{16}\Big)^{\dfrac{3}{4}} \times \Big[\Big(\dfrac{7}{3}\Big)^2\Big]^{\dfrac{3}{2}} ÷ \Big[\Big(\dfrac{7}{6}\Big)^3\Big]^{\dfrac{2}{3}} \\[1em] \Rightarrow \Big[\Big(\dfrac{3}{2}\Big)^4\Big]^{\dfrac{3}{4}} \times \Big[\Big(\dfrac{7}{3}\Big)^2\Big]^{\dfrac{3}{2}} ÷ \Big[\Big(\dfrac{7}{6}\Big)^3\Big]^{\dfrac{2}{3}} \\[1em] \Rightarrow \Big(\dfrac{3}{2}\Big)^3 \times \Big(\dfrac{7}{3}\Big)^3 ÷ \Big(\dfrac{7}{6}\Big)^2 \\[1em] \Rightarrow \Big(\dfrac{27}{8}\Big) \times \Big[\Big(\dfrac{343}{27}\Big) ÷ \Big(\dfrac{49}{36}\Big)\Big] \\[1em] \Rightarrow \Big(\dfrac{27}{8}\Big) \times \Big[\Big(\dfrac{343}{27}\Big) \times \Big(\dfrac{36}{49}\Big)\Big] \\[1em] \Rightarrow \Big(\dfrac{27}{8}\Big) \times \Big(\dfrac{7}{3}\Big) \times 4 \\[1em] \Rightarrow \Big(\dfrac{9}{2}\Big) \times 7 \\[1em] \Rightarrow \dfrac{63}{2} = 31\dfrac{1}{2}.

Hence, (1681)34×(499)32÷(343216)23=3112\Big(\dfrac{16}{81}\Big)^{-\dfrac{3}{4}} \times \Big(\dfrac{49}{9}\Big)^{\dfrac{3}{2}} ÷ \Big(\dfrac{343}{216}\Big)^{\dfrac{2}{3}} = 31\dfrac{1}{2}.

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