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Mathematics

Evaluate the following:

(i) 23×60\dfrac{2}{3} \times 60

(ii) 47×280\dfrac{4}{7} \times 280

(iii) 23\dfrac{2}{3} of 1491\dfrac{4}{9}

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Answer

(i) 23×60\dfrac{2}{3} \times 60

2×6032×2040\Rightarrow \dfrac{2 \times 60}{3}\\[1em] \Rightarrow 2 \times 20\\[1em] \Rightarrow 40

Hence, 23×60=40\dfrac{2}{3} \times 60 = 40.

(ii) 47×280\dfrac{4}{7} \times 280

4×28074×40160\Rightarrow \dfrac{4 \times 280}{7}\\[1em] \Rightarrow 4 \times 40\\[1em] \Rightarrow 160

Hence, 47×280=160\dfrac{4}{7} \times 280 = 160.

(iii) 23\dfrac{2}{3} of 1491\dfrac{4}{9}

23×14923×1392×133×92627\Rightarrow \dfrac{2}{3} \times 1\dfrac{4}{9}\\[1em] \Rightarrow \dfrac{2}{3} \times \dfrac{13}{9}\\[1em] \Rightarrow \dfrac{2 \times 13}{3 \times 9}\\[1em] \Rightarrow \dfrac{26}{27}

Hence, 23\dfrac{2}{3} of 149=26271\dfrac{4}{9} = \dfrac{26}{27}.

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