Mathematics

Examine the following numbers for divisibility by 6:

(i) 93573

(ii) 217944

(iii) 5034126

(iv) 901352

(v) 639210

(vi) 1790184

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Answer

A number is divisible by 6 if it is divisible by both 2 and 3.

(i) 93573 — last digit 3, not divisible by 2.

Hence, 93573 is not divisible by 6.

(ii) 217944 — last digit 4, divisible by 2.

Sum of digits = 2 + 1 + 7 + 9 + 4 + 4 = 27, divisible by 3.

Hence, 217944 is divisible by 6.

(iii) 5034126 — last digit 6, divisible by 2.

Sum of digits = 5 + 0 + 3 + 4 + 1 + 2 + 6 = 21, divisible by 3.

Hence, 5034126 is divisible by 6.

(iv) 901352 — last digit 2, divisible by 2.

Sum of digits = 9 + 0 + 1 + 3 + 5 + 2 = 20, not divisible by 3.

Hence, 901352 is not divisible by 6.

(v) 639210 — last digit 0, divisible by 2.

Sum of digits = 6 + 3 + 9 + 2 + 1 + 0 = 21, divisible by 3.

Hence, 639210 is divisible by 6.

(vi) 1790184 — last digit 4, divisible by 2.

Sum of digits = 1 + 7 + 9 + 0 + 1 + 8 + 4 = 30, divisible by 3.

Hence, 1790184 is divisible by 6.

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