(2a \+ b) 3 Using the formula, (x \+ y) 3 = x 3 \+ y 3 \+ 3x 2 y \+ 3xy 2 = (2a) 3 \+ b 3 \+ 3 x (2a) 2 x (b) \+ 3 x (2a) x (b) 2 = 8a 3 \+ b 3 \+ 12a 2 b \+ 6ab 2 Hence, (2a \+ b) 3 = 8a 3 \+ b 3 \+ 12a 2 b \+ 6ab 2

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(2a + b)³

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(2a + b)³

Using the formula,

(x + y)³ = x³ + y³ + 3x²y + 3xy²

= (2a)³ + b³ + 3 x (2a)²x (b) + 3 x (2a) x (b)²

= 8a³ + b³ + 12a²b + 6ab²

Hence, (2a + b)³ = 8a³ + b³ + 12a²b + 6ab²

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(2a + b)³

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Related Questions

Find the square of:
$x +\dfrac{1}{x}- 1$

Evaluate using expansion of (a + b)² or (a - b)² :
(i) (208)²
(ii) (92)²
(iii) (9.4)²
(iv) (20.7)²

Expand:
(a - 2b)³

Expand:
(3x - 2y)³

Mathematics

Expand:(2a + b)3

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Answer

Related Questions

Find the square of:x+1x−1x +\dfrac{1}{x}- 1x+x1​−1

Evaluate using expansion of (a + b)2 or (a - b)2 :(i) (208)2(ii) (92)2(iii) (9.4)2(iv) (20.7)2

Expand:(a - 2b)3

Expand:(3x - 2y)3

Expand:
(2a + b)³

Find the square of:
$x +\dfrac{1}{x}- 1$

Evaluate using expansion of (a + b)² or (a - b)² :
(i) (208)²
(ii) (92)²
(iii) (9.4)²
(iv) (20.7)²

Expand:
(a - 2b)³

Expand:
(3x - 2y)³