Expand (3x + 5y + 2z)(3x - 5y + 2z)
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Given,
⇒ (3x + 5y + 2z)(3x - 5y + 2z)
⇒ 9x2 - 15xy + 6xz + 15xy - 25y2 + 10yz + 6zx - 10yz + 4z2
⇒ 9x2 - 25y2 + 4z2 + 12xz.
Hence, (3x + 5y + 2z)(3x - 5y + 2z) = 9x2 - 25y2 + 4z2 + 12xz.
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If 2x - 3y = 10 and xy = 16, find the value of 8x3 - 27y3.
Expand (3x - 5y - 2z)(3x - 5y + 2z)
The sum of two numbers is 9 and their product is 20. Find the sum of their :
(i) squares
(ii) cubes.