Using the formula, [∵ (x \+ y) 3 = x 3 \+ y 3 \+ 3x 2 y \+ 3xy 2 ] So, ⇒ (5x \+ 3y) 3 = (5x) 3 \+ (3y) 3 \+ 3 (5x) 2 (3y) \+ 3 (5x) (3y) 2 = 125x 3 \+ 27y 3 \+ 225x 2 y \+ 135xy 2 Hence, (5x \+ 3y) 3 = 125x 3 \+ 27y 3 \+ 225x 2 y \+ 135xy 2 .

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(3x - 4y + 5z)²

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(2a - 5b - 4c)²

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(6a - 7b)³

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If a + b + c = 9 and ab + bc + ca = 15, find: a² + b² + c².

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Mathematics

Expand:
(5x + 3y)³

Identities

Related Questions

Expand:
(3x - 4y + 5z)²

Expand:
(2a - 5b - 4c)²

Expand:
(6a - 7b)³

If a + b + c = 9 and ab + bc + ca = 15, find: a² + b² + c².

Mathematics

Expand:(5x + 3y)3

Identities

Related Questions

Expand:(3x - 4y + 5z)2

Expand:(2a - 5b - 4c)2

Expand:(6a - 7b)3

If a + b + c = 9 and ab + bc + ca = 15, find: a2 + b2 + c2.

Expand:
(5x + 3y)³

Expand:
(3x - 4y + 5z)²

Expand:
(2a - 5b - 4c)²

Expand:
(6a - 7b)³

If a + b + c = 9 and ab + bc + ca = 15, find: a² + b² + c².