Using the formula, [∵ (x \- y) 3 = x 3 \- y 3 \- 3x 2 y \+ 3xy 2 ] So, ⇒ (6a \- 7b) 3 = (6a) 3 \- (7b) 3 \- 3 (6a) 2 (7b) \+ 3 (6a) (7b) 2 = 216a 3 \- 343b 3 \- 756a 2 b \+ 882ab 2 Hence, (6a \- 7b) 3 = 216a 3 \- 343b 3 \- 756a 2 b \+ 882ab 2 .

Expand:
(2a - 5b - 4c)²

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Expand:
(5x + 3y)³

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If a + b + c = 9 and ab + bc + ca = 15, find: a² + b² + c².

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If a + b + c = 11 and a² + b² + c² = 81, find: ab + bc + ca.

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Mathematics

Expand:
(6a - 7b)³

Identities

Related Questions

Expand:
(2a - 5b - 4c)²

Expand:
(5x + 3y)³

If a + b + c = 9 and ab + bc + ca = 15, find: a² + b² + c².

If a + b + c = 11 and a² + b² + c² = 81, find: ab + bc + ca.

Mathematics

Expand:(6a - 7b)3

Identities

Related Questions

Expand:(2a - 5b - 4c)2

Expand:(5x + 3y)3

If a + b + c = 9 and ab + bc + ca = 15, find: a2 + b2 + c2.

If a + b + c = 11 and a2 + b2 + c2 = 81, find: ab + bc + ca.

Expand:
(6a - 7b)³

Expand:
(2a - 5b - 4c)²

Expand:
(5x + 3y)³

If a + b + c = 9 and ab + bc + ca = 15, find: a² + b² + c².

If a + b + c = 11 and a² + b² + c² = 81, find: ab + bc + ca.