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(a - b + c)2
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(a - b + c)2
Using the formula,
[∵ (x - y + z)2 = x2 + y2 + z2 - 2xy - 2yz + 2xz]
= a2 + b2 + c2 - 2ab - 2bc + 2ca
Hence, (a + b - c)2 = a2 + b2 + c2 - 2ab - 2bc + 2ca
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Expand:
(a - b + c)2
5 Likes
(a - b + c)2
Using the formula,
[∵ (x - y + z)2 = x2 + y2 + z2 - 2xy - 2yz + 2xz]
= a2 + b2 + c2 - 2ab - 2bc + 2ca
Hence, (a + b - c)2 = a2 + b2 + c2 - 2ab - 2bc + 2ca
Answered By
4 Likes