Factorise :
81x4−16y481x^4 - 16y^481x4−16y4
2 Likes
81x4−16y4=(9x2)2−(4y2)2=(9x2−4y2)(9x2+4y2)=((3x)2−(2y)2)(9x2+4y2)=(3x−2y)(3x+2y)(9x2+4y2)81x^4 - 16y^4\\[1em] = (9x^2)^2 - (4y^2)^2\\[1em] = \Big(9x^2 - 4y^2\Big)\Big(9x^2 + 4y^2\Big)\\[1em] = \Big((3x)^2 - (2y)^2\Big)\Big(9x^2 + 4y^2\Big)\\[1em] = (3x - 2y)(3x + 2y)(9x^2 + 4y^2)81x4−16y4=(9x2)2−(4y2)2=(9x2−4y2)(9x2+4y2)=((3x)2−(2y)2)(9x2+4y2)=(3x−2y)(3x+2y)(9x2+4y2)
Hence, 81x4−16y4=(3x−2y)(3x+2y)(9x2+4y2)81x^4 - 16y^4 = (3x - 2y)(3x + 2y)(9x^2 + 4y^2)81x4−16y4=(3x−2y)(3x+2y)(9x2+4y2).
Answered By
1 Like
(2x−y)2−14x+7y−18(2x - y)^2 - 14x + 7y - 18(2x−y)2−14x+7y−18
98(a+b)2−298(a + b)^2 - 298(a+b)2−2
(2a+b)3−(a+2b)3(2a + b)^3 - (a + 2b)^3(2a+b)3−(a+2b)3
Solve :
3x-5y+1=02x-y+3=0
