Mathematics
Factorise:
2a3 + 16b3 - 3a - 6b
Factorisation
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Answer
Given,
⇒ 2a3 + 16b3 - 3a - 6b
⇒ (2a3 + 16b3) - (3a + 6b)
⇒ 2(a3 + 8b3) - 3(a + 2b)
⇒ 2[(a)3 + (2b)3] - 3(a + 2b)
⇒ 2(a + 2b)[(a)2 - a × 2b + (2b)2] - 3(a + 2b)
⇒ 2(a + 2b)(a2 - 2ab + 4b2) - 3(a + 2b)
⇒ (a + 2b)[2(a2 - 2ab + 4b2) - 3]
Hence, 2a3 + 16b3 - 3a - 6b = (a + 2b)[2(a2 - 2ab + 4b2) - 3].
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