Factorise :
3a2 - 1 - 2a
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Given,
= 3a2 - 2a - 1
= 3a2 - 3a + a - 1
= 3a(a - 1) + 1(a - 1)
= (a - 1)(3a + 1).
Hence, 3a2 - 1 - 2a = (a - 1)(3a + 1).
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(2a + b)2 - 6a - 3b - 4
1 - 2a - 2b - 3(a + b)2
x2 + 3x + 2 + ax + 2a
(3x - 2y)2 + 3(3x - 2y) - 10