Factorise : 3a^2x - bx + 3a^2 - b

3a 2 x \- bx \+ 3a 2 \- b = x(3a 2 \- b) \+ 1(3a 2 \- b) = (3a 2 \- b)(x \+ 1) Hence,3a 2 x \- bx \+ 3a 2 \- b = (3a 2 \- b)(x \+ 1)

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3a²x - bx + 3a² - b

= x(3a² - b) + 1(3a² - b)

= (3a² - b)(x + 1)

Hence,3a²x - bx + 3a² - b = (3a² - b)(x + 1)

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