Factorise :
(3x - 2y)2 + 3(3x - 2y) - 10
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Given,
Substituting (3x - 2y) = a, we get :
⇒ a2 + 3a - 10
= a2 + 5a - 2a - 10
= a(a + 5) - 2(a + 5)
= (a + 5)(a - 2)
= (3x - 2y + 5)(3x - 2y - 2).
Hence, (3x - 2y)2 + 3(3x - 2y) - 10 = (3x - 2y + 5)(3x - 2y - 2).
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3a2 - 1 - 2a
x2 + 3x + 2 + ax + 2a
5 - (3a2 - 2a)(6 - 3a2 + 2a)
x4 - 1 in the form of factors is :
(x + 1)(x - 1)(x2 - 1)
(x - 1)(x + 1)(x2 + 1)
(x - 1)(x - 2)(x2 + 2)
(x + 1)(x + 2)(x2 - 1)