Mathematics
Factorise :
4a2b - 9b3
Factorisation
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Answer
Given,
4a2b - 9b3
= b[4a2 - 9b2]
= b[(2a)2 - (3b)2]
= b(2a + 3b)(2a - 3b).
Hence, 4a2b - 9b3 = b(2a + 3b)(2a - 3b).
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Factorise :
4a2b - 9b3
25 Likes
Given,
4a2b - 9b3
= b[4a2 - 9b2]
= b[(2a)2 - (3b)2]
= b(2a + 3b)(2a - 3b).
Hence, 4a2b - 9b3 = b(2a + 3b)(2a - 3b).
Answered By
14 Likes