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Mathematics

Factorise :

(623)2(213)2\Big(6\dfrac{2}{3}\Big)^2 - \Big(2\dfrac{1}{3}\Big)^2

Factorisation

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Answer

(623)2(213)2\Big(6\dfrac{2}{3}\Big)^2 - \Big(2\dfrac{1}{3}\Big)^2

= (203)2(73)2\Big(\dfrac{20}{3}\Big)^2 - \Big(\dfrac{7}{3}\Big)^2

Using the formula

[∵ (x2 - y2) = (x + y)(x - y)]

=(203+73)(20373)=((20+7)3)((207)3)=(273)(133)=(27×133×3)=(3519)=39= \Big(\dfrac{20}{3} + \dfrac{7}{3}\Big)\Big(\dfrac{20}{3} - \dfrac{7}{3}\Big)\\[1em] = \Big(\dfrac{(20 + 7)}{3}\Big)\Big(\dfrac{(20 - 7)}{3}\Big)\\[1em] = \Big(\dfrac{27}{3}\Big)\Big(\dfrac{13}{3}\Big)\\[1em] = \Big(\dfrac{27 \times 13}{3 \times 3}\Big)\\[1em] = \Big(\dfrac{351}{9}\Big)\\[1em] = 39

Hence,(623)2(213)2\Big(6\dfrac{2}{3}\Big)^2 - \Big(2\dfrac{1}{3}\Big)^2 = 39

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