Mathematics
Factorise:
7a3 + 56b3
Factorisation
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Answer
Given,
⇒ 7a3 + 56b3
⇒ 7(a3 + 8b3)
⇒ 7[a3 + (2b)3]
By using the identity,
a3 + b3 = (a + b)(a2 - ab + b2)
⇒ 7(a + 2b)(a2 - a × 2b + (2b)2)
⇒ 7(a + 2b)(a2 - 2ab + 4b2).
Hence, 7a3 + 56b3 = 7(a + 2b)(a2 - 2ab + 4b2).
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