Mathematics
Factorise:
8a3 - b3 - 4ax + 2bx
Factorisation
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Answer
Given,
⇒ 8a3 - b3 - 4ax + 2bx
⇒ 8a3 - b3 - 4ax + 2bx
⇒ (2a)3 - (b)3 - 2x(2a - b)
By using the identity,
(a3 - b3) = (a - b)(a2 + ab + b2)
⇒ (2a - b)[(2a)2 + 2a × b + (b)2] - 2x(2a - b)
⇒ (2a - b)(4a2 + 2ab + b2) - 2x(2a - b)
⇒ (2a - b)(4a2 + 2ab + b2 - 2x).
Hence, 8a3 - b3 - 4ax + 2bx = (2a - b)(4a2 + 2ab + b2 - 2x).
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