Factorise:
a - 8ab3
3 Likes
Given,
⇒ a - 8ab3
⇒ a(1 - 8b3)
⇒ a[(1)3 - (2b)3]
By using the identity,
(a3 - b3) = (a - b)(a2 + ab + b2)
⇒ a(1 - 2b)[(1)2 + 1 × 2b + (2b)2]
⇒ a(1 - 2b)(1 + 2b + 4b2).
Hence, a - 8ab3 = a(1 - 2b)(1 + 2b + 4b2).
Answered By
1 Like
x6 - 1
a3 - 0.064