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Mathematics

Factorise :

8a3 - b3 - 4ax + 2bx

Factorisation

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Answer

Given,

    8a3 - b3 - 4ax + 2bx

= (2a)3 - (b)3 - 2x(2a - b)

= (2a - b)[(2a)2 + 2a × b + (b)2] - 2x(2a - b)

= (2a - b)(4a2 + 2ab + b2) - 2x(2a - b)

= (2a - b)(4a2 + 2ab + b2 - 2x).

Hence, 8a3 - b3 - 4ax + 2bx = (2a - b)(4a2 + 2ab + b2 - 2x).

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